Questions from Calculus


Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y' = 2 cos y, y(0) = 0

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y' = 5 + 4y - y2, y(0) = 1

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y' = y2 + y, y(0) = - 13

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y' = y2 - 2y + 1, y(0) = -1

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y' = ln y, y(0) = 2

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Q: Consider the differential equation y’ = .2(10 - y

Consider the differential equation y’ = .2(10 - y) from Example 6. If the initial temperature of the steel rod is 510˚, the function f (t) = 10 + 500 e-0.2t is the solution of the differential equati...

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y’ = 1 + cos y, y(0) = - 3/4

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y’ = 1/ (y2 + 1), y(0) = -1

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y’ = 3/(y + 3), y(0) = 2

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Q: Sketch the solution of the differential equation. Also indicate the constant

Sketch the solution of the differential equation. Also indicate the constant solution. y’ = .4y2(1 - y), y(0) = -1, y(0) = .1, y(0) = 2

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