Questions from General Calculus

Q: Use Newton’s method to approximate the indicated root of the equation correct

Use Newton’s method to approximate the indicated root of the equation correct to six decimal places. The positive root of 3 sin x = x

Q: Use Newton’s method to find all solutions of the equation correct to

Use Newton’s method to find all solutions of the equation correct to six decimal places. 3 cox x = x + 1

Q: Use Newton’s method to find all solutions of the equation correct to

Use Newton’s method to find all solutions of the equation correct to six decimal places. 2x = 2 – x2

Q: Use Newton’s method to find all solutions of the equation correct to

Use Newton’s method to find all solutions of the equation correct to six decimal places. sin x = x2 - 2

Q: Use Newton’s method to find all the solutions of the equation correct

Use Newton’s method to find all the solutions of the equation correct to eight decimal places. Start by drawing a graph to find initial approximations. -2x7 - 5x4 + 9x3 + 5 = 0

Q: Use Newton’s method to find all the solutions of the equation correct

Use Newton’s method to find all the solutions of the equation correct to eight decimal places. Start by drawing a graph to find initial approximations. x5 - 3x4 + x3 - x2 - x + 6 = 0

Q: Differentiate the function. T(z) = 2z log

Differentiate the function. T(z) = 2z log 2z

Q: Use Newton’s method to find all the solutions of the equation correct

Use Newton’s method to find all the solutions of the equation correct to eight decimal places. Start by drawing a graph to find initial approximations. cos (x2 - x) = x4

Q: Explain why Newton’s method doesn’t work for finding the root of the

Explain why Newton’s method doesn’t work for finding the root of the equation x3 - 3x + 6 = 0 if the initial approximation is chosen to be x1 = 1.

Q: (a) Use Newton’s method with x1 = 1 to find

(a) Use Newton’s method with x1 = 1 to find the root of the equation x3 - x = 1 correct to six decimal places. (b) Solve the equation in part (a) using x1 = 0.6 as the initial approximation. (c) Solve...