Q: The engineer of a passenger train traveling at 25.0 m
The engineer of a passenger train traveling at 25.0 m/s sights a freight train whose caboose is 200 m ahead on the same track (Fig. P2.62). The freight train is traveling at 15.0 m/s in the same direc...
See AnswerQ: A ball starts from rest and rolls down a hill with uniform
A ball starts from rest and rolls down a hill with uniform acceleration, traveling 200 m during the second 5.0 s of its motion. How far did it roll during the first 5.0 s of motion?
See AnswerQ: Two cars start 200 m apart and drive toward each other at
Two cars start 200 m apart and drive toward each other at a steady 10 m/s. On the front of one of them, an energetic grasshopper jumps back and forth between the cars (he has strong legs!) with a cons...
See AnswerQ: A car and a truck start from rest at the same instant
A car and a truck start from rest at the same instant, with the car initially at some distance behind the truck. The truck has a constant acceleration of 2.10 m/s2, and the car has an acceleration of...
See AnswerQ: You are standing at rest at a bus stop. A bus
You are standing at rest at a bus stop. A bus moving at a constant speed of 5.00 m/s passes you. When the rear of the bus is 12.0 m past you, you realize that it is your bus, so you start to run towar...
See AnswerQ: The driver of a car wishes to pass a truck that is
The driver of a car wishes to pass a truck that is traveling at a constant speed of 20.0 m/s (about 45 mi/h). Initially, the car is also traveling at 20.0 m/s, and its front bumper is 24.0 m behind th...
See AnswerQ: An object’s velocity is measured to be vx(t) =
An object’s velocity is measured to be vx(t) = a - bt2, where a = 4.00 m/s and b = 2.00 m/s3. At t = 0 the object is at x = 0. (a) Calculate the object’s position and acceleration as functions of time...
See AnswerQ: In uniform circular motion, what are the average velocity and average
In uniform circular motion, what are the average velocity and average acceleration for one revolution? Explain.
See AnswerQ: The acceleration of a particle is given by ax(t)
The acceleration of a particle is given by ax(t) = -2.00 m/s2 +(3.00 m/s3)t. (a) Find the initial velocity v0x such that the particle will have the same x-coordinate at t = 4.00 s as it had at t = 0....
See AnswerQ: You are on the roof of the physics building, 46.
You are on the roof of the physics building, 46.0 m above the ground (Fig. P2.70). Your physics professor, who is 1.80 m tall, is walking alongside the building at a constant speed of 1.20 m/s. If you...
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